From Mechanics
F=d2Gm1m2
where
F
is the force on a particle on the surface of Mars,
m1
is the mass of Mars,
m2
is the mass of the particle and
d
is the radius of Mars.
As
F=m2a
where
a
is the acceleration of the particle on Mars,
a=d2Gm1
As
G=6.67
10−11 kg-1m3s-2
we get
a=
3.4106m
26.6710−11 kg-1m3s-2
6.421023kg=1.732106.677.38ms−2=1.64ms−2
