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Solution 4.6a

From Mechanics

Revision as of 15:22, 23 March 2010 by Ian (Talk | contribs)
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F=Fcosi+Fsinj


F1=40 N and 1=20 this gives


F1=40cos20i+40sin20j=400.94i+400.342j=37.6i+13.7j N


F2=50 N and 2=−30 this gives


F2=50cos−30i+50sin−30j=500.866i−500.50j=43.3i+25j N

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