4.4 Exercises
From Förberedande kurs i matematik 1
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Current revision
| Theory | Exercises |
Exercise 4.4:1
For which angles 
v2
| a) | | b) | |
| c) | | d) | |
| e) | | f) | |
| g) |  3 |
Answer | Solution a | Solution b | Solution c | Solution d | Solution e | Solution f | Solution g
Loading...Exercise 4.4:2
Solve the equation
| a) | 3 | b) | | c) | |
| d) | 2 | e) | | f) | 2 |
Answer | Solution a | Solution b | Solution c | Solution d | Solution e | Solution f
Exercise 4.4:3
Solve the equation
| a) | 6 | b) | \displaystyle \sin{x}=\sin{\displaystyle \frac{\pi}{5}} |
| c) | \displaystyle \sin{(x+40^\circ)}=\sin{65^\circ} | d) | \displaystyle \sin{3x}=\sin{15^\circ} |
Answer | Solution a | Solution b | Solution c | Solution d
Exercise 4.4:4
Determine the angles \displaystyle \,v\, in the interval \displaystyle \,0^\circ \leq v \leq 360^\circ\, which satisfy \displaystyle \ \cos{\left(2v+10^\circ\right)}=\cos{110^\circ}\,.
Exercise 4.4:5
Solve the equation
| a) | \displaystyle \sin{3x}=\sin{x} | b) | \displaystyle \tan{x}=\tan{4x} |
| c) | \displaystyle \cos{5x}=\cos(x+\pi/5) |
Answer | Solution a | Solution b | Solution c
Exercise 4.4:6
Solve the equation
| a) | \displaystyle \sin x\cdot \cos 3x = 2\sin x | b) | \displaystyle \sqrt{2}\sin{x}\cos{x}=\cos{x} |
| c) | \displaystyle \sin 2x = -\sin x |
Answer | Solution a | Solution b | Solution c
Exercise 4.4:7
Solve the equation
| a) | \displaystyle 2\sin^2{x}+\sin{x}=1 | b) | \displaystyle 2\sin^2{x}-3\cos{x}=0 |
| c) | \displaystyle \cos{3x}=\sin{4x} |
Answer | Solution a | Solution b | Solution c
Exercise 4.4:8
Solve the equation
| a) | \displaystyle \sin{2x}=\sqrt{2}\cos{x} | b) | \displaystyle \sin{x}=\sqrt{3}\cos{x} |
| c) | \displaystyle \displaystyle \frac{1}{\cos^2{x}}=1-\tan{x} |
Answer | Solution a | Solution b | Solution c
