2.2 Integration durch Substitution
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Version vom 08:17, 17. Sep. 2008
| Exercises |
Contents:
- Integration by substitution
Learning outcomes:
After this section, you will have learned to:
- Understand the derivation of the formula for variable substitution .
- Solve simple integration problems that require rewriting and / or substitution in one of the steps.
- Know how the limits of integration are to be changed after a variable substitution.
- Know when variable substitution is allowed.
Variable substitution
When you cannot directly determine a primitive function by using the usual rules of differentiation ”in the opposite direction” method, other methods or techniques are needed. One such is variable substitution, which can be said to be based on the rule for the differentiation of composite functions — the so-called chain rule.
The chain rule (u(x))
u
(x)
- REDIRECT Template:Abgesetzte Formel
or,
- REDIRECT Template:Abgesetzte Formel
where F is a primitive function of f. We compare this with the formula
- REDIRECT Template:Abgesetzte Formel
We can see that we have replaced the term (x)dx
u
(x)
u
(x)
Note 1 The method is based on the assumption that all the conditions for integration are satisfied; that is,
Note 2 Replacing (x)dx
- REDIRECT Template:Abgesetzte Formel
which, as x
- REDIRECT Template:Abgesetzte Formel
ie., a small change, (x)dx
Example 1
Determine the integral2xex2dx
If one puts (x)=2x
(x)dx
- REDIRECT Template:Abgesetzte Formel
Example 2
Determine the integral (x3+1)3
x2dx
Put =3x2
- REDIRECT Template:Abgesetzte Formel
Example 3
Determine the integral \displaystyle \ \int \tan x \, dx\,\mbox{,}\ \ where \displaystyle -\pi/2 < x < \pi/2.
After rewriting \displaystyle \tan x as \displaystyle \sin x/\cos x we substitute \displaystyle u=\cos x,
- REDIRECT Template:Abgesetzte Formel
The limits of integration during variable substitution.
When calculating definite integrals, such as an area, one can go about using variable substitution in two ways. Either one can calculate the integral as usual and then switch back to the original variable and insert the original limits of integration. Alternatively one can change the limits of integration simultaneously with the variable substitution. The two methods are illustrated in the following example.
Example 4
Determine the integral \displaystyle \ \int_{0}^{2} \frac{e^x}{1 + e^x} \, dx.
Method 1
Put \displaystyle u=e^x which gives that \displaystyle u'= e^x and \displaystyle du= e^x\,dx
- REDIRECT Template:Abgesetzte Formel
Note that the limits of integration must be written in the form \displaystyle x = 0 and \displaystyle x = 2 when the variable of integration is not \displaystyle x. it is wrong to write
- REDIRECT Template:Abgesetzte Formel
Method 2
Put \displaystyle u=e^x which gives that \displaystyle u'= e^x and \displaystyle du= e^x\, dx. The limit of integration \displaystyle x=0 is equivalent to \displaystyle u=e^0 = 1 and \displaystyle x=2 is equivalent to \displaystyle u=e^2
- REDIRECT Template:Abgesetzte Formel
Example 5
Determine the integral \displaystyle \ \int_{0}^{\pi/2} \sin^3 x\,\cos x \, dx.
The substitution \displaystyle u=\sin x gives \displaystyle du=\cos x\,dx and the limits of integration become \displaystyle u=\sin 0=0 and \displaystyle u=\sin(\pi/2)=1. The integral is
- REDIRECT Template:Abgesetzte Formel
The figure on the left shows the graph of the integrand sin³x cos x and the figure on the right the graph of integrand u³ which is obtained after the variable substitution. The change of variable modifies the integrand and the interval of the integration. The integrals value, the size of the area, is not changed however. |
Example 6
Examine the following calculation
- REDIRECT Template:Abgesetzte Formel
This calculation, however, is wrong, which is due to the fact that \displaystyle f(u)=1/u^2 is not continuous throughout the interval \displaystyle [-1,1]. A necessary condition in the theory is that \displaystyle f(u(x)) be defined and continuous for all values which \displaystyle u(x) can take in the interval in question. Otherwise one cannot be certain that the substitution \displaystyle u=u(x) will work. |
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