Processing Math: Done
To print higher-resolution math symbols, click the
Hi-Res Fonts for Printing button on the jsMath control panel.
jsMath

Lösung 3.4:1a

Aus Online Mathematik Brückenkurs 2

(Unterschied zwischen Versionen)
Wechseln zu: Navigation, Suche
K (Lösning 3.4:1a moved to Solution 3.4:1a: Robot: moved page)
Zeile 1: Zeile 1:
-
{{NAVCONTENT_START}}
+
The numerator can be factorized using the conjugate rule to give
-
<center> [[Image:3_4_1a.gif]] </center>
+
<math>x^{2}-1=\left( x+1 \right)\left( x-1 \right)</math>
-
{{NAVCONTENT_STOP}}
+
and then we see that the numerator and denominator have a common factor which we can eliminate
 +
 
 +
 
 +
<math>\frac{x^{2}-1}{x-1}=\frac{\left( x+1 \right)\left( x-1 \right)}{x-1}=x+1</math>

Version vom 12:30, 26. Okt. 2008

The numerator can be factorized using the conjugate rule to give x2−1=x+1x−1  and then we see that the numerator and denominator have a common factor which we can eliminate


x−1x2−1=x−1x+1x−1=x+1 

Von „http://wiki.math.se/wikis/2009/bridgecourse2-TU-Berlin/index.php/L%C3%B6sung_3.4:1a“