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Lösung 1.2:3d

Aus Online Mathematik Brückenkurs 2

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Version vom 10:06, 11. Mär. 2009

We differentiate the function successively, one part at a time,

ddxsincossinx=coscossinxcossinx 

and the next differentiation becomes

ddxcossinx=sinsinxsinx=sinsinxcosx.

The answer is thus

ddxsincossinx=coscossinx(sinsinxcosx)=coscossinxsinsinxcosx.