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Lösung 1.3:2b

Aus Online Mathematik Brückenkurs 2

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Version vom 10:09, 11. Mär. 2009

In order to determine the function's extreme points, we investigate three types of points,

  1. critical points, i.e. where f(x)=0,
  2. points where the function is not differentiable, and
  3. endpoints of the interval of definition.

In our case, we have that:

  1. The derivative of f(x) is given by
    f(x)=32x
    and becomes zero when x=32.
  2. The function is a polynomial, and is therefore differentiable everywhere.
  3. The function is defined for all x, and therefore the interval of definition has no endpoints.

There is thus just one point x=32, where the function possibly has an extreme point.

If we write down a sign table for the derivative, we see that x=32 is a local maximum.


x 23
f(x) + 0
f(x) 417


Because the function is given by a second-degree expression, its graph is a parabola with a maximum at (32174) and we can draw it with the help of a few couple of points.