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Lösung 2.1:1d

Aus Online Mathematik Brückenkurs 2

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Version vom 10:14, 11. Mär. 2009

The modulus function, x, strips x of its sign, e.g.

−5=5, 3=3 and −=.

For positive values of x, the modulus function has no effect, since x=x, but for negative x the modulus function changes the sign of x, i.e. x=−x (remember that x is negative and therefore −x is positive).

If we draw a graph of y=x it will consist of two parts. For x0 we have y=x, and for x0 we have y=−x.

The value of the integral is the area of the region under the graph y=x and between x=−1 and x=2.

This region consists of two triangles and we therefore obtain

2−1xdx=2111+2122=25. 
Von „http://wiki.math.se/wikis/2009/bridgecourse2-TU-Berlin/index.php/L%C3%B6sung_2.1:1d“