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Lösung 2.1:2d

Aus Online Mathematik Brückenkurs 2

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Version vom 10:16, 11. Mär. 2009

If we rewrite x  as x12 , the integrand can then be simplified using the power laws,

41x2xdx=41x2x12dx=41x122dx=41x32dx. 

We can now use the fact that a primitive function for xn is xn+1(n+1) and calculate the integral's value,

41x32dx= x32+132+1 41= 12x12 41= 21x12 41= 2x 41=2421=22+2=1.