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Lösung 3.1:1d

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Version vom 10:29, 11. Mär. 2009

We expand the expression by multiplying each term in the first bracket with every term in the second bracket,

(32i)(7+5i)=37+35i+=37+35i2i72i5i.

Then, we use that i2=1 and write the real and imaginary parts together,

(32i)(7+5i)=21+15i14i10i2=21+15i14i10(1)=(21+10)+(15i14i)=31+(1514)i=31+i.