Processing Math: Done
To print higher-resolution math symbols, click the
Hi-Res Fonts for Printing button on the jsMath control panel.
No jsMath TeX fonts found -- using image fonts instead.
These may be slow and might not print well.
Use the jsMath control panel to get additional information.
jsMath Control PanelHide this Message

jsMath

Lösung 1.2:2d

Aus Online Mathematik Brückenkurs 2

(Unterschied zwischen Versionen)
Wechseln zu: Navigation, Suche
K (Robot: Automated text replacement (-{{Displayed math +{{Abgesetzte Formel))
K (Solution 1.2:2d moved to Lösung 1.2:2d: Robot: moved page)

Version vom 10:04, 11. Mär. 2009

We can see the expression as "ln of something",

ln

where "something" is lnx.

Because we have a compound expression, we use the chain rule and obtain, roughly speaking, the outer derivative multiplied by the inner derivative,

ddxlnlnx=1lnxlnx 

where the first factor on the right-hand side 1lnx is the outer derivative of lnlnx and the other factor lnx  is the inner derivative. Thus, we get

ddxlnlnx=1lnxx1=1xlnx.
Von „http://wiki.math.se/wikis/2009/bridgecourse2-TU-Berlin/index.php/L%C3%B6sung_1.2:2d“