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Lösung 2.1:3c

Aus Online Mathematik Brückenkurs 2

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Version vom 10:17, 11. Mär. 2009

If we multiply the factors in the integrand together and use the power laws,

e2xex+1dx=e2xex+e2xdx=e2x+x+e2xdx=e3x+e2xdx

we obtain a standard integral with two terms of the type eax, where a is a constant. The indefinite integral is therefore

e3x+e2xdx=3e3x+2e2x+C 

where C is an arbitrary constant.

Von „http://wiki.math.se/wikis/2009/bridgecourse2-TU-Berlin/index.php/L%C3%B6sung_2.1:3c“