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Antwort 1.2:1

Aus Online Mathematik Brückenkurs 2

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(Ny sida: {| width="100%" cellspacing="10px" |a) |width="33%"| <math>\cos^2x-\sin^2x=\cos2x</math> |b) |width="33%"| <math>2x\ln x+ x</math> |c) |width="33%"| <math>\displaystyle\frac{x^2+2x-1}{(x+1)...)
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Version vom 07:58, 4. Apr. 2008

a) cos2x−sin2x=cos2x b) 2xlnx+x c) (x+1)2x2+2x−1=1−2(x+1)2
d) xcosx−x2sinx e) 1lnx−1(lnx)2 f) sinxlnx+1−sin2xxlnxcosx
Von „http://wiki.math.se/wikis/2009/bridgecourse2-TU-Berlin/index.php/Antwort_1.2:1“