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Lösung 3.2:6b

Aus Online Mathematik Brückenkurs 2

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K (Lösning 3.2:6b moved to Solution 3.2:6b: Robot: moved page)
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If we determine the number's magnitude
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<center> [[Image:3_2_6b.gif]] </center>
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<math>r</math>
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and argument
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<math>\alpha </math>, we can write its polar form using the formula
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<math>r\left( \cos \alpha +i\sin \alpha \right)</math>
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Because the number lies on the imaginary axis, it is possible to write its magnitude and argument directly:
[[Image:3_2_6_b.gif|center]]
[[Image:3_2_6_b.gif|center]]
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The polar form is
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<math>11\left( \cos \frac{3\pi }{2}+i\sin \frac{3\pi }{2} \right)</math>.

Version vom 10:17, 23. Okt. 2008

If we determine the number's magnitude r and argument , we can write its polar form using the formula


rcos+isin 


Because the number lies on the imaginary axis, it is possible to write its magnitude and argument directly:



The polar form is


11cos23+isin23 .

Von „http://wiki.math.se/wikis/2009/bridgecourse2-TU-Berlin/index.php/L%C3%B6sung_3.2:6b“