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Lösung 1.1:2a

Aus Online Mathematik Brückenkurs 2

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Version vom 09:58, 11. Mär. 2009

By using the rule for differentiation

ddxxn=nxn−1

and the fact that the expression can be differentiated term by term and that constant factors can be taken outside the differentiation, we obtain

f(x)=ddxx2−3x+1=ddxx2−3ddxx1+ddx1=2x2−1−31x1−1+0=2x−3.
Von „http://wiki.math.se/wikis/2009/bridgecourse2-TU-Berlin/index.php/L%C3%B6sung_1.1:2a“