Processing Math: Done
Lösung 1.2:2c
Aus Online Mathematik Brückenkurs 2
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Version vom 10:04, 11. Mär. 2009
When we see this expression, we should think "square root of something",
 , |
and in order to differentiate it, we should first differentiate the outer function , "the square root of", with respect to its argument and, after that, multiply by the derivative of the inner functional expression
cosx=12 cosx  cosx   |
where we have used the differentiation rule
 x=ddxx1 2=21x12−1=21x−12=12x. |
Thus, we obtain
| cosx=12cosx(−sinx)=−sinx2cosx. |
