Processing Math: Done
Lösung 1.2:3a
Aus Online Mathematik Brückenkurs 2
(Unterschied zwischen Versionen)
K (Robot: Automated text replacement (-{{Displayed math +{{Abgesetzte Formel)) |
K (Solution 1.2:3a moved to Lösung 1.2:3a: Robot: moved page) |
Version vom 10:05, 11. Mär. 2009
There is a "ln of something", so a first step in the differentiation is to take the derivative of the logarithm,
  x+x+1 =1x+x+1 x+x+1 . |
We can carry out the differentiation of x+x+1
x+x+1 (x)+(x+1) |
and it remains then only to differentiate x x+1
x+x+1 12x+12x+1(x+1) =1x+x+112x+12x+11. |
If we rewrite the expression inside the square brackets using a common denominator, we get
x+x+12xx+1x+1+x |
and we can then eliminate the factor x+1+x
| xx+1. |
