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Antwort 1.3:3

Aus Online Mathematik Brückenkurs 2

(Unterschied zwischen Versionen)
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Aktuelle Version (09:54, 5. Aug. 2009) (bearbeiten) (rückgängig)
 
Zeile 1: Zeile 1:
{| width="100%" cellspacing="10px"
{| width="100%" cellspacing="10px"
|a)
|a)
-
|width="50%"| <math>x=0\,</math> (Lokales Maxima)
+
|width="50%"| <math>x=0\,</math> (Lokales Maximum)
|b)
|b)
-
|width="50%"| <math>x=-\frac{1}{3}\ln\frac{5}{3}\,</math> (Lokales Minima)
+
|width="50%"| <math>x=-\frac{1}{3}\ln\frac{5}{3}\,</math> (Lokales Minimum)
|-
|-
|-
|-
|c)
|c)
-
|width="50%"| <math>x=1/e\,</math> (Lokales Minima)
+
|width="50%"| <math>x=1/e\,</math> (Lokales Minimum)
|d)
|d)
|width="50%"|
|width="50%"|
-
<math>x=-\sqrt{\sqrt{2}-1}\,</math> (Lokales Maxima)
+
<math>x=-\sqrt{\sqrt{2}-1}\,</math> (Lokales Maximum)
-
<math>x=0\,</math> (Lokales Minima)
+
<math>x=0\,</math> (Lokales Minimum)
-
<math>x=\sqrt{\sqrt{2}-1}\,</math> (Lokales Maxima)
+
<math>x=\sqrt{\sqrt{2}-1}\,</math> (Lokales Maximum)
|-
|-
|e)
|e)
-
|width="50%"| <math>x=-3\,</math> (Lokales Minima)
+
|width="50%"| <math>x=-3\,</math> (Lokales Minimum)
-
<math>x=-2\,</math> (Lokales Maxima)
+
<math>x=-2\,</math> (Lokales Maximum)
-
<math>x=1\,</math> (Lokales Minima)
+
<math>x=1\,</math> (Lokales Minimum)
-
<math>x=3\,</math> (Lokales Maxima)
+
<math>x=3\,</math> (Lokales Maximum)
|}
|}

Aktuelle Version

a) x=0 (Lokales Maximum) b) x=−31ln35 (Lokales Minimum)
c) x=1e (Lokales Minimum) d)

x=−2−1  (Lokales Maximum)

x=0 (Lokales Minimum)

x=2−1  (Lokales Maximum)

e) x=−3 (Lokales Minimum)

x=−2 (Lokales Maximum)

x=1 (Lokales Minimum)

x=3 (Lokales Maximum)

Von „http://wiki.math.se/wikis/2009/bridgecourse2-TU-Berlin/index.php/Antwort_1.3:3“