Antwort 3.4:7
Aus Online Mathematik Brückenkurs 2
(Unterschied zwischen Versionen)
(Ny sida: <math>(z-1)(z-2)(z-4) = z^3 -7z^2 + 14z - 8</math>) |
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| Zeile 1: | Zeile 1: | ||
| - | <math>(z-1)(z-2)(z-4) = z^3 -7z^2 + 14z - 8</math> | + | {| width="100%" cellspacing="10px" |
| + | |a) | ||
| + | |width="50%"| <math>(z-1)(z-2)(z-4) = z^3 -7z^2 + 14z - 8</math> | ||
| + | |b) | ||
| + | |width="50%"| <math>(z+1-i)(z+1+i) = z^2+2z+2</math> | ||
| + | |} | ||
Version vom 14:54, 7. Apr. 2008
| a) | \displaystyle (z-1)(z-2)(z-4) = z^3 -7z^2 + 14z - 8 | b) | \displaystyle (z+1-i)(z+1+i) = z^2+2z+2 |
