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Antwort 3.4:7

Aus Online Mathematik Brückenkurs 2

(Unterschied zwischen Versionen)
Wechseln zu: Navigation, Suche
(Ny sida: <math>(z-1)(z-2)(z-4) = z^3 -7z^2 + 14z - 8</math>)
Zeile 1: Zeile 1:
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<math>(z-1)(z-2)(z-4) = z^3 -7z^2 + 14z - 8</math>
+
{| width="100%" cellspacing="10px"
 +
|a)
 +
|width="50%"| <math>(z-1)(z-2)(z-4) = z^3 -7z^2 + 14z - 8</math>
 +
|b)
 +
|width="50%"| <math>(z+1-i)(z+1+i) = z^2+2z+2</math>
 +
|}

Version vom 14:54, 7. Apr. 2008

a) (z−1)(z−2)(z−4)=z3−7z2+14z−8 b) (z+1−i)(z+1+i)=z2+2z+2
Von „http://wiki.math.se/wikis/2009/bridgecourse2-TU-Berlin/index.php/Antwort_3.4:7“