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Lösung 1.2:1d

Aus Online Mathematik Brückenkurs 2

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We have a quotient between sinx and x, and therefore one way to differentiate the expression is to use the quotient rule:


xsinx=x2sinxxsinxx=x2cosxxsinx1=xcosxx2sinx

It is also possible to see the expression as a product of

sinx and x1, and to use the product rule,


sinxx1=sinxx1+sinxx1=cosxx1+sinx1x2=xcosxx2sinx


where we have used


x1=x1=1x11=1x2=1x2