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Lösung 1.1:2c

Aus Online Mathematik Brückenkurs 2

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We differentiate term by term:


fx=ddxex−lnx=ddxex−ddxlnx=ex−x1


NOTE: because ln x is not defined for x0 we assume implicitly that x0.

Von „http://wiki.math.se/wikis/2009/bridgecourse2-TU-Berlin/index.php/L%C3%B6sung_1.1:2c“