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Lösung 1.2:2d

Aus Online Mathematik Brückenkurs 2

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We can see the expression as "ln of something",


ln,

where "something" is lnx.

Because we have a compound expression, we use the chain rule and obtain, roughly speaking, the outer derivative multiplied by the inner derivative,


ddxlnlnx=1lnxlnx 


where the first factor on the right-hand side 1lnx is the outer derivative of lnlnx and the other factor lnx  is the inner derivative. Thus, we get


ddxlnlnx=1lnxx1=1xlnx