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Lösung 1.2:3d

Version vom 13:18, 12. Okt. 2008 von Ian (Diskussion | Beiträge)

We differentiate the function successively, one part at a time,

ddxsincossinx=coscossinxcossinx ,

and the next differentiation becomes

ddxcossinx=−sinsinxsinx=−sinsinxcosx

The answer is thus

ddxsincossinx=coscossinx−sinsinxcosx=−coscossinxsinsinxcosx