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Lösung 1.2:3d

Aus Online Mathematik Brückenkurs 2

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We differentiate the function successively, one part at a time,


ddxsincossinx=coscossinxcossinx ,

and the next differentiation becomes


ddxcossinx=−sinsinxsinx=−sinsinxcosx


The answer is thus


ddxsincossinx=coscossinx−sinsinxcosx=−coscossinxsinsinxcosx

Von „http://wiki.math.se/wikis/2009/bridgecourse2-TU-Berlin/index.php/L%C3%B6sung_1.2:3d“