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Aus Online Mathematik Brückenkurs 2

If we rewrite x  as x12 , the integrand can then be simplified using the power laws:

41x2xdx=41x2x21dx=41x21−2dx=41x−23dx 

We can now use the fact that a primitive function for xn is xn+1n+1 and calculate the integral's value:

41x−23dx=−23+1x−23+141=−21x−2141=−21x1241=−2x41=−24−−21=−22+2=1