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Lösung 2.2:2a
Aus Online Mathematik Brückenkurs 2
The integral is a standard integral, with
0cos5xdx=
u=5xdu=
5x
dx=5dx
=51
5
0cosudu
As can be seen, the variable change replaced
0=0
=5
Now, we have a standard integral which can easily compute:
5
0cosudu=51
sinu
05
=51
sin5
−sin0
=51
0−0
=0
NOTE: if we draw the graph for