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Lösung 3.3:2b

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The The equation z3=1 is a so-called binomial equation, which we solve by writing both sides in polar form. We have


z=rcos+isin1=1cos+isin 


and, with the help of de Moivre's formula, the equation becomes


r3cos3+isin3=1cos+isin 


Both sides are equal when their magnitudes are equal and the arguments differ by a multiple of 2,


r3=13=+2nn an arbitrary integer  

which gives that


r=1=3+32nn an arbitrary integer  


For every third integer n, the solution formula gives in principal the same value for the argument (the difference is a multiple of 2), so the equation has in reality three solutions (for n=0 1 and 2):


z=1cos3+isin31cos+isin1cos35+isin35=21+i3121i3

We obtain the typical behaviour that the solutions are corner points in a regular polygon (a triangle in this case because the degree of the equation is 3).