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Aus Online Mathematik Brückenkurs 2

By using the rule for differentiation

ddxxn=nxn−1

and the fact that the expression can be differentiated term by term and that constant factors can be taken outside the differentiation, we obtain

f(x)=ddxx2−3x+1=ddxx2−3ddxx1+ddx1=2x2−1−31x1−1+0=2x−3.