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Lösung 2.2:1c

Aus Online Mathematik Brückenkurs 2

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With the given variable substitution, u=x3, we obtain

du=x3dx=3x2dx 

and because the integral contains x2 as a factor, we can bundle it together with dx and replace the combination with 31du,

ex3x2dx=u=x3=eu31du=31eu+C. 

Thus, the answer is

ex3x2dx=31ex3+C 

where C is an arbitrary constant.

Von „http://wiki.math.se/wikis/2009/bridgecourse2-TU-Berlin/index.php/L%C3%B6sung_2.2:1c“