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Lösung 3.4:1a

Aus Online Mathematik Brückenkurs 2

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The numerator can be factorized using the formula for the difference of two squares to give x2−1=(x+1)(x−1) and then we see that the numerator and denominator have a common factor which we can eliminate

x−1x2−1=x−1(x+1)(x−1)=x+1.
Von „http://wiki.math.se/wikis/2009/bridgecourse2-TU-Berlin/index.php/L%C3%B6sung_3.4:1a“