Solution 10.1b
From Mechanics
Here \displaystyle T is the tension in the cable and \displaystyle a is the acceleration of the packet.
Applying Newton's second law
\displaystyle \begin{align} & \downarrow :\ \text{Resultant}\ \text{Force}=300\times 9 \textrm{.}81-T= ma = 300\times 0 \textrm{.}2 \\ & \\ & T=2943-60\approx 2880\ \text{N} \\ \end{align}