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Solution 13.2

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Force Perpendicular Moment (Nm)
distance (m)
8 N at D 2 −82=−16
20 N at D 0 200=0
18 N at C 5 −185=−90
16 N at C 2 162=32
24 N at B 0 240=0
Total Moment −16+0−90+32+0=−74 Nm
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