Solution 5.1b

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The forces on the particle are in equilibrium as the particle is at rest.

The sum of the forces in the normal direction (resolving in the normal direction)

\displaystyle \begin{align} & R-mg\cos {{20}^{\circ }}=0 \\ & \\ & R=mg\cos {{20}^{\circ }}=20\times 9\textrm{.}8\times 0\textrm{.}94=184\ \text{N} \\ \end{align}