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Solution 5.6c

From Mechanics

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First the maximum friction must be calculated.

To do this we need the normal reaction force R.

Resolving in the normal direction

Rmgcos20=0R=729.80.94=663 N

Then the maximim friction F is

R=0.2663=132 N

The gravitational force which we denote as G1, down the slope is

G1=mgsin20=729.80.342=241 N

The forces are in equilibrium down the slope. If we denote the air resistance force as F1, we get,

G1F1F=0

giving

F1=G1F=241132=109 N