Processing Math: Done

From Mechanics

We use the result from part a).

r=(8 i+8 j)t+21(0.01i+0.02j+0.1k)t 2+10k , for any time t.

At the end when t=40 also from part a), we get

r=(8 i+8 j)40+21(0.01i+0.02j+0.1k)40 2+10k=328i+336j+10k , for any time t.

The car starts at the origin and finishes at 328i+336j.

The magnitude of this position vector is the distance D  travelled.

D=3282+3362=107584+112896=220480=470 m