From Mechanics

In the figure \displaystyle T represents the tension in the tow rope.

The forces on the car must be in equilibrium.

Resolving along the hill in the upward direction,

\displaystyle \begin{align} & T\cos {{7}^{\circ }}-mg\sin {{5}^{\circ }}=0 \\ & \\ & T=\frac{mg\sin {{5}^{\circ }}}{\cos {{7}^{\circ }}}=\frac{1600\times 9\textrm{.}81\times 0\textrm{.}0872}{0\textrm{.}992}=\frac{1368}{0\textrm{.}992}=1379\simeq 1380\ \text{N} \\ \end{align}