From Mechanics

From part a) \displaystyle \ T=1380 \text{ N}.

Resolving perpendicular to the hill,

\displaystyle \begin{align} & R+T\sin {{7}^{\circ }}-mg\cos {{5}^{\circ }}=0 \\ & \\ & R=mg\cos {{5}^{\circ }}-T\sin {{7}^{\circ }}=1600\times 9\textrm{.}81\times 0\textrm{.}996-1380\times 0\textrm{.}122= \\ & =15633-168=15465\simeq 15500\ \text{N} \\ \end{align}