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Solution 9.5

From Mechanics

Revision as of 12:42, 18 May 2010 by Ian (Talk | contribs)
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Image:9.5.gif

In the figure R1 is the air resistance.

Resolving up the plane

F1+Fmgsin20=0F1=mgsin20F=609.810.342F=201.3 NF

Resolving perpendicular to the plane upwards

Rmgcos20=0R=mgcos20=609.810.94=553 N

Using the friction equation gives

F=R=0.05553=27.65 N

Substituting in the above equation for R1 gives

F1=201.327.65173 N