Processing Math: Done
To print higher-resolution math symbols, click the
Hi-Res Fonts for Printing button on the jsMath control panel.
No jsMath TeX fonts found -- using image fonts instead.
These may be slow and might not print well.
Use the jsMath control panel to get additional information.
jsMath Control PanelHide this Message

jsMath

Solution 9.5

From Mechanics

Revision as of 09:56, 6 March 2011 by Ian (Talk | contribs)
(diff) ←Older revision | Current revision (diff) | Newer revision→ (diff)
Jump to: navigation, search

Image:9.5a.gif

In the figure F1 is the air resistance.

Resolving up the plane

F1+F−mgsin20=0F1=mgsin20−F=609.810.342−F=201.3 N−F

Resolving perpendicular to the plane upwards

R−mgcos20=0R=mgcos20=609.810.94=553 N

Using the friction equation gives

F=R=0.05553=27.65 N

Substituting in the above equation for R1 gives

F1=201.3−27.65173 N

Retrieved from "http://wiki.math.se/wikis/2009/bridgecoursemechanics/index.php/Solution_9.5"