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Svar 2.1:6

Förberedande kurs i matematik 1

(Skillnad mellan versioner)
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(Ny sida: {| width="100%" cellspacing="10px" |a) |width="50%" | <math>2y</math> |b) |width="50%" | <math>\displaystyle\frac{-x+12}{(x-2)(x+3)}</math> |- |c) |width="50%" | <math>\displaystyle\frac{b...)
Nuvarande version (31 mars 2008 kl. 12.05) (redigera) (ogör)
(Ny sida: {| width="100%" cellspacing="10px" |a) |width="50%" | <math>2y</math> |b) |width="50%" | <math>\displaystyle\frac{-x+12}{(x-2)(x+3)}</math> |- |c) |width="50%" | <math>\displaystyle\frac{b...)
 

Nuvarande version

a) 2y b) x+12(x2)(x+3)
c) ba(ab) d) 4ba(a+b)