Processing Math: Done
Lösung 3.3:3a
Aus Online Mathematik Brückenkurs 2
(Unterschied zwischen Versionen)
K (Lösning 3.3:3a moved to Solution 3.3:3a: Robot: moved page) |
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- | {{ | + | When we complete the square of the second degree expression, |
- | < | + | <math>z^{2}+2z+3</math> |
- | {{ | + | we start with the squaring rule |
+ | |||
+ | |||
+ | <math>\left( z+a \right)^{2}=z^{2}+2az+a^{2}</math> | ||
+ | |||
+ | |||
+ | which we write as | ||
+ | |||
+ | |||
+ | <math>\left( z+a \right)^{2}-a^{2}=z^{2}+2az</math> | ||
+ | |||
+ | |||
+ | and adapt the constant to be | ||
+ | <math>a=\text{1 }</math> | ||
+ | so that the terms | ||
+ | <math>z^{2}+2z</math> | ||
+ | are equal to | ||
+ | <math>z^{2}+2az</math>,, and therefore can be written as | ||
+ | <math>\left( z+1 \right)^{2}-1^{2}</math>. The whole calculation becomes | ||
+ | |||
+ | |||
+ | <math>\underline{z^{2}+2z}+3=\underline{\left( z+1 \right)^{2}-1^{2}}+3=\left( z+1 \right)^{2}+2</math> | ||
+ | |||
+ | |||
+ | The underline terms show the actual completion of the square. |
Version vom 08:31, 25. Okt. 2008
When we complete the square of the second degree expression,
z+a
2=z2+2az+a2
which we write as
z+a
2−a2=z2+2az
and adapt the constant to be
z+1
2−12
z+1
2−12+3=
z+1
2+2
The underline terms show the actual completion of the square.