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Lösung 3.2:2b

Aus Online Mathematik Brückenkurs 2

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The inequality <math>0\leq \mathop{\rm Re} z \leq \mathop{\rm Im} z \leq 1</math> is actually several inequalities:
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The inequality <math>0\leq \mathrm{Re}z \leq \mathrm{Im}z \leq 1</math> is actually several inequalities:
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<math>\begin{align}
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:*<math>0 \leq \mathop{\rm Re} z \leq 1\,</math>,
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0 &\leq \mathrm{Re}z \leq 1,\\
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:*<math>0 \leq \mathop{\rm Im}z \leq 1\,</math>,
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0 &\leq \mathrm{Im}z \leq 1,\end{align}</math>
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:*<math>\mathop{\rm Re}z \leq \mathop{\rm Im}z\,\textrm{.}</math>
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<math>\mathrm{Re}z \leq \mathrm{Im}z
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</math>.
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The first two inequalities in this list define the unit square in the complex number plane.
The first two inequalities in this list define the unit square in the complex number plane.
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[[Image:3_2_2_b1.gif|center]]
[[Image:3_2_2_b1.gif|center]]
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The last inequality says that the real part of <math>z</math> should be less than or equal to the imaginary part of <math>z</math>, I.e. <math>z</math> should lie to the left of the line <math>y=x</math> if <math>x=\mathrm{Re} z</math> and <math>y = \mathrm{Im} z</math>.
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The last inequality says that the real part of <math>z</math> should be less than or equal to the imaginary part of <math>z</math>, i.e. <math>z</math> should lie to the left of the line <math>y=x</math> if <math>x=\mathop{\rm Re} z</math> and <math>y = \mathop{\rm Im} z</math>.
[[Image:3_2_2_b2.gif|center]]
[[Image:3_2_2_b2.gif|center]]
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[[Image:3_2_2_b3.gif|center]]
[[Image:3_2_2_b3.gif|center]]
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Version vom 09:38, 29. Okt. 2008

The inequality 0RezImz1 is actually several inequalities:

  • 0Rez1,
  • 0Imz1,
  • RezImz.

The first two inequalities in this list define the unit square in the complex number plane.

The last inequality says that the real part of z should be less than or equal to the imaginary part of z, i.e. z should lie to the left of the line y=x if x=Rez and y=Imz.

All together, the inequalities define the region which the unit square and the half-plane have in common: a triangle with corner points at 0, i and 1+i.