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Lösung 1.2:1b

Aus Online Mathematik Brückenkurs 2

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We use the product rule with <math>x^2</math> and <math>\ln x</math> as factors,
We use the product rule with <math>x^2</math> and <math>\ln x</math> as factors,
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{{Displayed math||<math>\begin{align}
+
{{Abgesetzte Formel||<math>\begin{align}
\bigl(x^{2}\ln x\bigr)'
\bigl(x^{2}\ln x\bigr)'
&= \bigl(x^2\bigr)'\,\ln x + x^2\,(\ln x)'\\[5pt]
&= \bigl(x^2\bigr)'\,\ln x + x^2\,(\ln x)'\\[5pt]

Version vom 12:52, 10. Mär. 2009

We use the product rule with x2 and lnx as factors,

x2lnx=x2lnx+x2(lnx)=2xlnx+x2x1=2xlnx+x.