Processing Math: 66%
3.1 Übungen
Aus Online Mathematik Brückenkurs 2
(Unterschied zwischen Versionen)
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|width="50%"| <math>i^{\,20} + i^{\,11}</math> | |width="50%"| <math>i^{\,20} + i^{\,11}</math> | ||
|} | |} | ||
- | </div>{{#NAVCONTENT: | + | </div>{{#NAVCONTENT:Antwort|Antwort 3.1:1|Solution a|Solution 3.1:1a|Solution b|Solution 3.1:1b|Solution c|Solution 3.1:1c|Solution d|Solution 3.1:1d|Solution e|Solution 3.1:1e|Solution f|Solution 3.1:1f}} |
===Übung 3.1:2=== | ===Übung 3.1:2=== | ||
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|width="50%"| <math>\displaystyle\frac{5-\displaystyle\frac{1}{1+i}}{3i + \displaystyle\frac{i}{2-3i}}</math> | |width="50%"| <math>\displaystyle\frac{5-\displaystyle\frac{1}{1+i}}{3i + \displaystyle\frac{i}{2-3i}}</math> | ||
|} | |} | ||
- | </div>{{#NAVCONTENT: | + | </div>{{#NAVCONTENT:Antwort|Antwort 3.1:2|Solution a|Solution 3.1:2a|Solution b|Solution 3.1:2b|Solution c|Solution 3.1:2c|Solution d|Solution 3.1:2d}} |
===Übung 3.1:3=== | ===Übung 3.1:3=== | ||
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- | </div>{{#NAVCONTENT: | + | </div>{{#NAVCONTENT:Antwort|Antwort 3.1:3|Solution|Solution 3.1:3}} |
===Übung 3.1:4=== | ===Übung 3.1:4=== | ||
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|width="50%"| <math>(1+i)\overline{z}+iz = 3+5i</math> | |width="50%"| <math>(1+i)\overline{z}+iz = 3+5i</math> | ||
|} | |} | ||
- | </div>{{#NAVCONTENT: | + | </div>{{#NAVCONTENT:Antwort|Antwort 3.1:4|Solution a|Solution 3.1:4a|Solution b|Solution 3.1:4b|Solution c|Solution 3.1:4c|Solution d|Solution 3.1:4d|Solution e|Solution 3.1:4e|Solution f|Solution 3.1:4f}} |
Version vom 13:29, 10. Mär. 2009
Theorie | Übungen |
Übung 3.1:1
Write in the form
a) | b) | | |
c) | | d) | |
e) | | f) | |
Antwort | Solution a | Solution b | Solution c | Solution d | Solution e | Solution f
Übung 3.1:2
Write in the form
a) | b) | | |
c) | ![]() ![]() | d) | |
Antwort | Solution a | Solution b | Solution c | Solution d
Übung 3.1:3
Determine the real number \displaystyle \,a\, such that the expression \displaystyle \ \displaystyle\frac{3+i}{2+ai}\ becomes purely imaginary (i.e. the real part equals zero).
Übung 3.1:4
Solve the equations
a) | \displaystyle z+3i=2z-2 | b) | \displaystyle (2-i) z= 3+2i |
c) | \displaystyle iz+2= 2z-3 | d) | \displaystyle (2+i) \overline{z} = 1+i |
e) | \displaystyle \displaystyle\frac{iz+1}{z+i} = 3+i | f) | \displaystyle (1+i)\overline{z}+iz = 3+5i |
Antwort | Solution a | Solution b | Solution c | Solution d | Solution e | Solution f