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Lösung 3.1:4a

Aus Online Mathematik Brückenkurs 2

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Version vom 10:32, 11. Mär. 2009

A general strategy when solving equations is to try to get the unknown variable by itself on one side.

In this case, we start by subtracting z from both sides,

z+3i−z=2z−2−z.

Then we have a z left on the right-hand side,

3i=z−2.

We add 2 to both sides to remove the −2 from the right hand side,

3i+2=z−2+2

and after that we can just read off the solution,

2+3i=z.

To check that we have calculated correctly, we substitute z=2+3i into the original equation and see that it is satisfied,

LHSRHS=z+3i=2+3i+3i=2+6i=2z−2=2(2+3i)−2=4+6i−2=2+6i.
Von „http://wiki.math.se/wikis/2009/bridgecourse2-TU-Berlin/index.php/L%C3%B6sung_3.1:4a“