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Lösung 3.2:2e

Aus Online Mathematik Brückenkurs 2

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Version vom 10:36, 11. Mär. 2009

Because the expression contains both z and z, we write out z=x+iy, where x is the real part of z and y is the imaginary part. Thus, we have

  • Rez=x
  • i+z=i+(x−iy)=x+(1−y)i

and the condition becomes

x=x+(1−y)i0=(1−y)i

which means that y=1.

The set therefore consists of all complex numbers with imaginary part 1.

Von „http://wiki.math.se/wikis/2009/bridgecourse2-TU-Berlin/index.php/L%C3%B6sung_3.2:2e“