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Antwort 3.3:4

Aus Online Mathematik Brückenkurs 2

(Unterschied zwischen Versionen)
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K (Answer 3.3:4 moved to Antwort 3.3:4: Robot: moved page)
Aktuelle Version (11:25, 31. Jul. 2009) (bearbeiten) (rückgängig)
(Changed answer to 3.3:4c)
 
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|c)
|c)
-
|width="50%"| <math>z= \left\{\begin{matrix} -1 \\ \phantom{-}3 \\ \end{matrix}\right. </math>
+
|width="50%"| <math>z= \left\{\begin{matrix} -1+i\sqrt{2}\\ -1-i\sqrt{2} \end{matrix}\right. </math>
|d)
|d)
|width="50%"| <math>z= \left\{\begin{matrix} (1+i\sqrt{15})/4\\ (1-i\sqrt{15})/4 \end{matrix}\right.</math>
|width="50%"| <math>z= \left\{\begin{matrix} (1+i\sqrt{15})/4\\ (1-i\sqrt{15})/4 \end{matrix}\right.</math>
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Aktuelle Version

a) z=(1+i)2−(1+i)2  b) z=2+i2−i 
c) z=−1+i2−1−i2  d) z=(1+i15)4(1−i15)4 
Von „http://wiki.math.se/wikis/2009/bridgecourse2-TU-Berlin/index.php/Antwort_3.3:4“