Processing Math: Done
Antwort 3.3:4
Aus Online Mathematik Brückenkurs 2
(Unterschied zwischen Versionen)
(Ny sida: {| width="100%" cellspacing="10px" |a) |width="50%"|<math>z= \left\{\begin{matrix} \phantom{-}(1+i)/\sqrt{2}\\ -(1+i)/\sqrt{2}\\ \end{matrix}\right.</math> |b) |width="50%"| <math>z = \left...) |
(Changed answer to 3.3:4c) |
||
| (Der Versionsvergleich bezieht 2 dazwischen liegende Versionen mit ein.) | |||
| Zeile 6: | Zeile 6: | ||
|- | |- | ||
|c) | |c) | ||
| - | |width="50%"| <math>z= \left\{\begin{matrix} -1 \ | + | |width="50%"| <math>z= \left\{\begin{matrix} -1+i\sqrt{2}\\ -1-i\sqrt{2} \end{matrix}\right. </math> |
|d) | |d) | ||
|width="50%"| <math>z= \left\{\begin{matrix} (1+i\sqrt{15})/4\\ (1-i\sqrt{15})/4 \end{matrix}\right.</math> | |width="50%"| <math>z= \left\{\begin{matrix} (1+i\sqrt{15})/4\\ (1-i\sqrt{15})/4 \end{matrix}\right.</math> | ||
|} | |} | ||
Aktuelle Version
| a) |  (1+i)  2−(1+i)2 | b) | 2+i2−i |
| c) | −1+i2−1−i2 | d) | (1+i15)4(1−i15)4 |
