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Antwort 1.3:1
Aus Online Mathematik Brückenkurs 2
(Unterschied zwischen Versionen)
Zeile 104:
Zeile 104:
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- ||Strängt väx.:||<math>[-\tfrac{5}{2},-1]</math>, <math>[-\tfrac{1}{2},\tfrac{1}{2}]</math>
+ | valign="top" |Strängt väx.:
+ | valign="top" |<math>[-\tfrac{5}{2},-1]</math>, <math>[-\tfrac{1}{2},\tfrac{1}{2}]</math>
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Version vom 08:18, 8. Mai 2008
a)
Kritisk punkt: x = 0
Terasspunkt: Saknas
Lokalt min: x = 0
Lokalt max: Saknas
Globalt min: x = 0
Globalt max: Saknas
Strängt väx.: x 0
Strängt avt.: x 0
b)
Kritisk punkt: x = − 1 , x = 1
Terasspunkt: Saknas
Lokalt min: x = − 3 , x = 1
Lokalt max: x = − 1 , x = 2
Globalt min: x = − 3
Globalt max: x = − 1
Strängt väx.: [ − 3 − 1] , [1 2 ]
Strängt avt.: [ − 1 1 ]
c)
Kritisk punkt:
x = − 2 , x = − 1 , x = 2 1
Terasspunkt: x = − 1
Lokalt min: x = − 2 , x = 2
Lokalt max: x = − 3 , x = 2 1
Globalt min: x = − 2
Globalt max: x = − 3
Strängt väx.: [ − 2 2 1 ]
Strängt avt.: [ − 3 − 2] , [ 2 1 2 ]
d)
Kritisk punkt:
x = − 2 5 , x = 2 1
Terasspunkt: Saknas
Lokalt min:
x = − 2 5 , \displaystyle x=-\tfrac{1}{2} , \displaystyle x=2
Lokalt max:
\displaystyle x=-3 , \displaystyle x=-1 , \displaystyle x=\tfrac{1}{2}
Globalt min: \displaystyle x=-\tfrac{5}{2}
Globalt max: \displaystyle x=-1
Strängt väx.:
\displaystyle [-\tfrac{5}{2},-1] , \displaystyle [-\tfrac{1}{2},\tfrac{1}{2}]
Strängt avt.:
\displaystyle [-3,-\tfrac{5}{2}] , \displaystyle [-1,-\tfrac{1}{2}] , \displaystyle [\tfrac{1}{2},2]