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1.1:2a alternativ 1

Version vom 13:06, 5. Sep. 2009 von Ombtut3 (Diskussion | Beiträge)

f(x)=limh0hf(x+h)−f(x) wobei f(x)=x2−3x+1 f(x)=limh0h(x+h)2−3(x+h)+1−(x2−3x+1=limh0hx2+2hx+h2−3x−3h+1−x2+3x+1=limh0h2hx+h2−3h=limh02x+h−3=2x−3