Lösung 2.1:2a
Aus Online Mathematik Brückenkurs 2
The foremost difficulty with calculating an integral is finding a primitive function of the integrand. Once we have done that, the integral is calculated as the difference between the primitive function's values in the upper and lower limits of integration.
The integrand in our case consists of two terms in the form
xndx=xn+1n+1+C
on the terms individually to obtain that
x
=x2+12+1+3
x3+13+1
is a primitive function of the integrand.
The integrand's value is thus
20
x2+3x3
dx=
3x3+3
4x4
20=323+3
424−
303+3
404
=38+43
16=344
NOTE: One way to check that
x
=31x3+43x4
x
x
=31
x3
+43
x4
=31
3x2+43
4x3=x2+3x3
as the integrand.